| | |
| | | |
| | | @Value("${phoneUpEveryHour}") |
| | | private Integer phoneUpEveryHour; |
| | | @Value("${phoneEndHour}") |
| | | private Integer phoneEndHour; |
| | | |
| | | /** |
| | | * 查询单一任务(随访) |
| | |
| | | patTaskRelevance.setPhone(serviceSubtask1.getPhone()); |
| | | patTaskRelevance.setTelcode(serviceSubtask1.getPhone()); |
| | | patTaskRelevance.setAddr(serviceSubtask1.getAddr()); |
| | | patTaskRelevance.setDiagname(serviceSubtask1.getDiagname()); |
| | | patTaskRelevance.setDiagname(serviceSubtask1.getLeavediagname()); |
| | | patTaskRelevance.setPatid(serviceSubtask1.getPatid()); |
| | | patTaskRelevance.setSendStatus(serviceSubtask1.getSendstate()); |
| | | patTaskRelevance.setDeptCode(serviceSubtask1.getDeptcode()); |
| | |
| | | patTaskRelevance.setDeptName(serviceSubtask1.getDeptname()); |
| | | patTaskRelevance.setDeptCode(serviceSubtask1.getDeptcode()); |
| | | patTaskRelevance.setBedNo(serviceSubtask1.getBedNo()); |
| | | patTaskRelevance.setDiagname(serviceSubtask1.getDiagname()); |
| | | patTaskRelevance.setDiagname(serviceSubtask1.getLeavediagname()); |
| | | patTaskRelevance.setPatid(serviceSubtask1.getPatid()); |
| | | patTaskRelevance.setSendStatus(serviceSubtask1.getSendstate()); |
| | | patTaskRelevance.setLeavehospitaldistrictcode(serviceSubtask1.getLeavehospitaldistrictcode()); |
| | |
| | | //phoneCount() 通过给出的每个小时需要打出的电话量,算出到晚上8点一点能打出多少个电话,获取到总量 |
| | | //如果需要立即执行的数据量大于一天要执行的上限,则只取上限的数量,其它的则放回redis中 |
| | | count = Math.min(phoneCount(), (int) size); |
| | | cacheList = listOps.range("cache-0", 0, count - 1); |
| | | if (count != 0) { |
| | | cacheList = listOps.range("cache-0", 0, count - 1); |
| | | } |
| | | } |
| | | |
| | | log.error("任务拉取cache-0的值是多少:{}", cacheList); |
| | |
| | | PullTaskVO pullTaskVO = new PullTaskVO(); |
| | | String subId = subIds.get(i).trim(); |
| | | ServiceSubtask serviceSubtask = serviceSubtaskMapper.selectServiceSubtaskById(Long.valueOf(subId)); |
| | | if (ObjectUtils.isEmpty(serviceSubtask)) { |
| | | log.error("该subId有问题,在表中查询不到:{}", subId); |
| | | continue; |
| | | } |
| | | ServiceTask serviceTask = serviceTaskService.selectServiceTaskByTaskid(serviceSubtask.getTaskid()); |
| | | IvrTaskTemplate ivrTaskTemplate = ivrTaskTemplateService.selectIvrTaskTemplateByID(serviceSubtask.getTemplateid()); |
| | | if (ObjectUtils.isEmpty(ivrTaskTemplate)) continue; |
| | |
| | | //无人接听 |
| | | getSmsCompensate(Long.valueOf(phoneCallRecordVO.getTaskid())); |
| | | redisCache.deleteObject(phoneCallRecordVO.getTaskid() + "recordAccept-hungup"); |
| | | redisCache.removeElementFromList("cache-exist", phoneCallRecordVO.getTaskid()); |
| | | } else if (ObjectUtils.isNotEmpty(cacheObject) && String.valueOf(cacheObject).equals("2")) { |
| | | // if (phoneCallRecordVO.getAnswered() != null && phoneCallRecordVO.getAnswered() == true) { |
| | | log.error("有人接电话了,并且完了"); |
| | |
| | | redisCache.deleteObject(phoneCallRecordVO.getTaskid() + "recordAccept-hungup"); |
| | | } else { |
| | | //患者拒绝随访 |
| | | //先把该subId从cache_exist中剔除,只要有回调就剔除(目的是,尽快让cache-exist为空,去缓存下一批要打的电话;这里剔除不影响电话的正常业务) |
| | | redisCache.removeElementFromList("cache-exist", phoneCallRecordVO.getTaskid()); |
| | | ServiceSubtask serviceSubtask = new ServiceSubtask(); |
| | | serviceSubtask.setRemark("电话接通成功,患者拒绝随访"); |
| | | serviceSubtask.setId(Long.valueOf(phoneCallRecordVO.getTaskid())); |
| | |
| | | // 当前时间 |
| | | LocalTime currentTime = LocalTime.now(); |
| | | // 目标时间(晚上 8 点) |
| | | LocalTime targetTime = LocalTime.of(20, 0); |
| | | LocalTime targetTime = LocalTime.of(phoneEndHour, 0); |
| | | // 计算当前时间到目标时间的时长 |
| | | Duration duration = Duration.between(currentTime, targetTime); |
| | | // 获取剩余时间的小时数 |
| | | long remainingHours = duration.toHours(); |
| | | long remainingHours = 0; |
| | | long remainingMinutes = duration.toMinutes(); |
| | | //如果超过8点,就设置为0 |
| | | if (remainingHours < 0) remainingHours = 0; |
| | | //距离结束时间小于20分钟,就不拉取了 |
| | | if (remainingMinutes < 20) remainingHours = 0; |
| | | else if (remainingMinutes < 60 && remainingMinutes > 20) remainingHours = 1; |
| | | else if (remainingMinutes > 60) remainingHours = remainingMinutes / 60; |
| | | // 计算剩余可以打的电话数 |
| | | int remainingCalls = (int) (remainingHours * phoneUpEveryHour); |
| | | return remainingCalls; |